an aqueous solution of sulfuric acid 0.1M contains:
A. 0.1 moles of acid in 100ml of solution
B. 0.001 mol of solute in 1 liter of solution
C. 0.1 mol of acid in 10 liter of water
D. 1 ml of acid in 2 ml of solution
E. 0.0001 mol of acid in 1 ml solution
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Hi!
They have given us the value of Molarity/concentration.
As we know that molarity(M)=moles solute/volume solution in litres.
so, if we have 1ml solution(10^-3L) then the moles acid= M x volume= 10^-1 x 10^-3= 10^-4
which is equal to 0.0001 mol.
Hope it helps:)
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