With b = (x+3)(x+5), c = 5(x+3), with any value of x, x+5>5 so that b>c.

With a = 15 = 5x3, if you compare it with c = 5(x+3), c>a with every x greater than 0 (with x=0, a = c, or x<0, a>c)

=> a<c<b for all values of x that fit the criteria

Hope this help

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Thank you, I didn’t pay attention to the “each number is greater than zero part”

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You’re welcome! Ikr, it happens to me all the time lmao

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Hahaha

Thank you BTW!

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