i didn’t understand why the guy free falling will go back to the original thermal velocity that he was in when he opened the parachute as there will be more air resistance against him as the parachute has more surface area and his velocity is decreased
I ANSWERD C and not A
when you reach terminal velocity the weight = F friction
when the parachute has been deployed the drag force greatly increases, then he reaches terminal velocity again
Since the weight of the parachutist hasn’t changed, we will once again find that weight = F friction
so the graph should show the drag doing back to the original line