BMAT 2008 Section 2 Q27 physics distance

Answer is C

Dist covered by sound in air = dist covered by sound in steel.

Let the time taken for steel be x secs
Time taken for air = x+1.5 secs

Dist covered in air = 300 * (x+1.5)
Dist covered in steel = 4800 * x

Equating both we have 4500x= 450

X = 0.1

Thus dist of train = 0.1* 4800 = 480m

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image

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Hi, isn’t the time t=0.1s?

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You are absolutely right. Bad foot step by me. Danger sign when approaching the judgement day on Tuesday. :face_with_head_bandage:

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