Bmat 2019 q 12 math

[nihantokar]

answer is 11 can someone solve this on paper and send the solution? thanks!

[winter1]

[nihantokar]

could you explain what you did in this step?
thanks!!

[winter1]

I used this equation!

As m = -3 in this case, and
(X1, y1) = (1-p,2) = (3,2).
y-2 = -3*(x-3) → y = -3x+11

Similarly, (X2, Y2) = (6, 3p-1) = (6, -7)
y+7 = -3*(x-6) → y+7 = -3*(0-6), y+7 = 18, y = 11