BMAT 2022 q 16 Linear Equations


was able to get the Line equation for Q but how do unable to go any further. any help would be appreciated.

hi

P: y=3x+7
Q is parallel to P so has the same gradient of 3, and passes by point (0;2)
so Q: y=3X+2
R is perpendicular to P so the gradient P * gradient R = -1
3 * gradient R = -1
gradient R = -1/3
We know it intersects P on the y axis, so it passes by the point (0;7)
R: y=-1/3x+7

intersect when P=Q
3x+2=-1/3x+7
10x=15
x=15/10 = 2/2 + 1/2 = 1 + 1/2 option B)

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