Hi, I have some difficulties to solve this question. I would be glad if someone can solve this

The right answer is c

Hi, I have some difficulties to solve this question. I would be glad if someone can solve this

The right answer is c

hi

in the first experiment, n = 0,32/32 = 0,01 mol of methanol were used

in the second experiment, 1 mol is used, so 100 times more moles

Q = mc * change T = 100 * 4,2 * 10 = 4200

0,01 mol methanol yield 4200 J of heat transfer

so with 100 times more moles:

1 mol methanol yields 4200 * 100 = 420000 J = 420 kJ

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