Hi, I have some difficulties to solve this question. I would be glad if someone can solve this
The right answer is c
The right answer is c
hi
in the first experiment, n = 0,32/32 = 0,01 mol of methanol were used
in the second experiment, 1 mol is used, so 100 times more moles
Q = mc * change T = 100 * 4,2 * 10 = 4200
0,01 mol methanol yield 4200 J of heat transfer
so with 100 times more moles:
1 mol methanol yields 4200 * 100 = 420000 J = 420 kJ
2 Likes