Hi!
Carbon is burnt in excess oxygen so considering all the carbon in the compound is present in the carbon in CO2.
n(CO2)=4.77/44(Mr CO2)=0.1
Also the molar ratio of C:CO2=1:1
Moles of C=0.1
Mass C=0.112=1.2g
%=1.2/2100=60%
which is closest to 65 the answer is thus E.
There’s also a typo in the question! Remember the Mr of Oxygen is 16 not 6
2 Likes