nitrogen reacts with hydrogen to produce ammonia:
N2(g) + 3H2(g) ↔ 2NH3(g).
A mixture of 2.00mol of nitrogen, 6.00mol of hydrogen and 2.40mol of ammonia is allowed to reach equilibrium in a sealed vessel of volume 1 dm^3 under certain conditions.
It was found that 2.32mol of nitrogen were present in the equilibrium mixture. Whats the value of Kc under these conditions?
Answer is (1.76)^2 / (2.32)(6.96)^3. Why?
hello! this was a long question to write down and take a photo of it so here is a screenshot of what my answer would be
hope this clears it up
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how do you go from?
Kc = 2.48^2/2.326.96^3 to 1.76^2/2.326.96^3
also the stoichiometric coefficient of n2 and nh3 aren’t the same so the change in moles can’t be the same imo. the change in nh3 would be 2 x 0.32 ie a loss of 0.64 ie going from 2.4 to 1.76 as in the answer.
Rest the method is correct.
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i believe chat gpt made a mistake with the numbers but the method is enough to understand forsure
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