(Q8)

How do we solve this type of question quickly?

is there any trick?

answer is

(2n where n = 4)

2 × 2 × 2 × 2 = 16

(Q8)

How do we solve this type of question quickly?

is there any trick?

answer is

(2n where n = 4)

2 × 2 × 2 × 2 = 16

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I don’t believe so, this is the fastest way I think. Is the answer correct?

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yes.

can you explain please

Sure! I thought you did the calculation haha. So in meiosis, every spermatozoa which is haploid, which means it has half the chromosome number. which is 4 in this case. We are coming up with different combinations of these genes on the two chromatids.

So we have to use the calculation 2 to the power of n or 2^n. We always use this formula to calculate the numbers of genetically different gametes.

So here if it is 4, we do 2^4 which is 2x2x2x2 which gives 16.

Does this help?

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Thanks this really helped

I didn’t know that we can use this formula for different gametes also.

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Yes! Make sure you divide the number by two if they give the value for a normal body cell

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oh yeah right makes sense

thanks btw

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