Entalphy of formation chemistry

I don’t know the answer of the question A might be wrong

I think your answer is correct, we have the enthalpy of formation of NH3 as -46 so by multiplying it by 2 (because we have 2 moles here)the total delta H of formation would be -92. but here is not formation and is decomposition reaction so it will be 92

please let me know if something is wrong with my statement