hey, it seems straightforward but the second part is confusing
Hi!
At the positive cathode: the PbO2 (Pb has an oxidation number of +4) after discharge both plates (i.e the +ve and the -Ve) is covered with Pbso4 so the oxidation state changes from +4---->+2.
At the negative anode: Pb is oxidised from Pb to Pb 2+ , a change in oxidation number from 0 to 2.
hope it helps!
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