This is a question that many students struggle with, and it is actually simpler than you think.
Recall:
Avogadro’s Law
Equal volumes of all gases, at the same constant temperature and pressure, have an equal number of particles.
V∝n
At 1 atm and 0°C, 1 mole of gas has a volume of 22.4L
This means that we can base the stoichiometry of this question based off coefficients because there is a constant relationship between volume and moles for all of them.
Now onto the question, where we are told that 150 cm^3 of F_2 reacts with 100 cm^3 of Cl_2
3F_2(g) + Cl _2(g) → 2Cl F_3(g)
(150cm^3) (100cm^3)
If we look at their stoichiometric coefficients, they should be reacting in a 3:1 ratio.
This means that for every 3cm^3 of F_2(g) for every 1g of Cl _2(g). We also know that for every 3cm^3 of 3F_2(g) and 1g of Cl _2(g), we have 2cm^3 of Cl F_3 formed as a product.
So, 150cm^3 of F_2(g) will react with 50cm^3 of Cl_2(g), leaving 50cm^3 unreacted and in excess.
For products, we will have 100cm^3, since its 2cm^3 per 3cm^3 of 3F_2(g) and 1g of Cl _2(g).
Now, for our final answer, what is left at the end of the reaction?
Of course, we will have 100cm^3 of Cl F_3, however, we will also have all of the unreacted gas, which is 50cm^3 of Cl_2.
100cm^3 Cl F_3 + 50cm^3 Cl_2 = 150cm^3 total
\fcolorbox{red}{grey!30}{Therefore the answer is E, $150cm^3$}