In order to solve this we must know the equation representing the dependency of the resistance (R) of a cylindrically shaped conductor (e.g., a wire) upon the variables that affect it is: R = p\frac{L}{A},
where L represents the length of the wire (in meters), A represents the cross-sectional area of the wire (in meters2) and p represents the resistivity of the material (in ohm meter).

Using this, we can calculate: R = 1 \cdot 10^{-6}\Omega m \frac{2 m}{\pi \cdot (\frac{1}{2} 2 \cdot 10^{-3})^2} = \frac{2 \cdot 10^{-6}}{\pi \cdot 1 \cdot 10^{-6}} \Omega = \frac{2.0}{\pi}\Omega.

So the final answer is (E)

ps. a diameter is given, to get the radius of the wire we must divide the diameter by 2