IMAT 2019 Q59 [Expression]

Let’s solve this:

\frac{8^{2n} \cdot 4^n}{2^n} = (2^3)^{2n} \cdot (2^2)^n \cdot 2^{-n} = 2^{6n}\cdot 2^{2n} \cdot 2^{-n} = 2^{6n+2n-n} = 2^{7n}

So the solution is (C) 2^{7n}