IMAT 2019 Q60 [Charged Particles]

Two charged particles P and Q are 0.10 m apart. The charge on P is 1.50 × 10^{–7} C and the charge on Q is 1.50 × 10^{–7} C. Particle P experiences an electrostatic force of magnitude F because it is near to the charge on particle Q.

The distance between the two particles is increased to 0.20 m. The charge on P is increased to 4.50 × 10^{–7} C and the charge on Q is increased to 6.00 × 10^{–7} C.

What is the magnitude of the force that particle P experiences now?

A. \frac {F}{4}

B. 12F

C. 6F

D. \frac{3F}{4}

E. 3F

2 Likes

we calculate the
proportion of F1 /F2 .
for both F we go with this formula F=Kq1q2/r^2

4 Likes

Is the answer to this question E ?