IMAT 2019 Question 55

A stone of density 5.20 g / cm3
and volume 200 cm3
is completely submerged in a liquid of
density 1.20 g / cm3
.
What is the magnitude of the upthrust acting on the stone?
[gravitational field strength = 10.0 N / kg]

A) 6.40 N
B) 2.00 N
C) 10.4 N
D) 8.00 N
E) 2.40 N

Hi!

density = m/V
so m=1,20 * 200=240g
Fb=m * g=0,24 * 10=2,4N

Hope this helps!

1 Like