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Using the second Newton’s law, which states that the time rate of change of the momentum of a body is equal in both magnitude and direction to the force imposed on it. aka. F = ma
F = ma = T - mg, seeing that the rocket moves in the same way as the thrust T.
From there, dividing the equation by the mass (m) we can get the initial acceleration: a = \frac{T}{m} -g, so the correct answer is (A)
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