Hi!
Power = work/time
Work = power x time
Work = (100 W) x (1600 s)
Work = 160000 J
This work corresponds with the heat (Q) supplied to the liquid
Q = 160000 J
The specific latent heat (λ) of evaporation of the liquid is λ = Q/m
λ = (160000 J) / (200 g)
λ = 800 J/g
Answer is thus D
Hope it helps:)
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Thank you so much 
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