Answer: A
correct me if im wrong:
Reasoning for answer is,

wrong

Wrong. Both nitric and sulfuric acid are strong acids and will dissociate fully in into ions.

True.
wrong
Wrong. Both nitric and sulfuric acid are strong acids and will dissociate fully in into ions.
True.
for 3 what do u mean by â€śif it was a monoprotic strong acid, pH of 2 would be correctâ€ť? wouldnâ€™t the pH if it were monoprotic simply be log[0.05] which is around 1.3? also for diprotic we calculate ph by multiplying the concentration by 2 as in log[(0.05x2)], right?
Regarding:
1 Sulfuric acid is a strong acid which dissociates completely in water. All strong acids protons have a pKavalue smaller than 4. In this case sulfuric acid has 3.0 and 1.99 as pKa1 and pKa2 (according to my uni data).
2 Nitric acid has a pKa of 1.4 and is fully dissociated in water. So, you are right.
3 You have in your #1 statement said, H2SO4 does not release all its protons, and now you say in #3 that it releases more than one hydrogen ion!
We have monoprotic acids which are not strong (having pKa over 4).
So, we need to calculate [H+] to answer the question. In this case pH will be 1.
Thank you for your feedback. There are numerous information out there saying that a solution of H2SO4 will not completely release 2 protons at room temp and there are specific calculation methods for that but for IMAT level, I guess the approximate pH would be 1.
the best way to solve this is by using log rules. so we know that pH = log[H+], and as the first proton of H2SO4 fully dissociates we know that the ph = log[0.05]. Now, we need to simplify 0.05 into the standard form which will give us pH = log[5 * 10^2 ]. This can be further simplified to:
pH = (log[10^2] + log[5])
pH =log[10^2] log[5]
now we know that log of 10^2 = 2
therefore
pH= (2) log[5]
pH = 2  log[5]
You should know that the log (to the base 10) of any number less than 10 will be less than 1, and any number more than 1 will be more than 0. Therefore we know that log[5] equals a number between 0 and 1. This will mean that Yâ€™s pH, regardless of whether the second proton dissociates partially or not, will be less than 2.
I hope this helps.