Hi, can anyone help me solve these questions please?

In the first question, I got “3 in 8” by solving 1/2 * 3/4 = 3/8 because it’s asking **a boy** without the condition.

And then I solved the statement 1 of the other question with the same approach and got 1/2 * 1/4 = 1/8 (12.5%). However, the answer is 25%. I need some explanation on this!!

A mother and a father, neither of whom has cystic fibrosis, conceive a child who has the condition.

What is the likelihood that the same parents will have another child who is a boy without cystic fibrosis?

A. 1 in 4

B. 3 in 4

C. 1 in 2

**D. 3 in 8**

E. 1 in 8

A male child has haemophilia. Neither parent has the condition. The parents have a second child.

Which of the following statements could be correct about this family?

1 There is a 25% chance that the second child is a boy with haemophilia.

2 There is a 75% chance that the second child does not show the condition.

3 There is a 50% chance that the mother is a carrier.

[Assume no other mutations.]

A **1 and 2 only**

B 2 only

C 3 only

D 1 only

E 2 and 3 only