Imat 2022 question 53 physics


Hi can anyone answer this question for me?

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v^2-v0^2=2as → 2.0^2 m/s - 0 m/s=2a . 2.0 m → a=1 m/s^2
F=m.a → 4.0 N = m . 1.0 m/s^2 → m=4.0 kg

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I have corrected it now.

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u=2.0ms-1
v=0
s=2.0m
v^2-u^s=2as
0-4=2a2
-4/4=a
a = -1ms-^2
Force = mass
accelaration
Since, force is resistive it will be negative
-4N= mass*-1ms^-2
-4N/-1ms-^2=mass
mass=4 Kg

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you took initial velocity as 0 whereas final velocity should be zero
the expression is v^2 -u^2 =2as
where v is final velocity and u is initial velocity

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Thank you so much . :pray:t2:

No difference which one is initial and which is final. You end op with a positive number for the mass as we use the absolute values for all parameters.

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Have you got two different values for acceleration?! :innocent:
One in newtons and one in m/s^2?!

And what about the mass which is the question :thinking:

Oh sorry I didn’t notice, it was a typo I corrected it