Imat maths equations

[SaqibKhan]

Imat past papers 2016 Q55

[Ibraheem_Saeed]

Saqib! The answer is A
I am sharing the already done solution by @natali

IMAT 2016 Q55 [Simplification]

In order to solve this question, we need to know the difference of two squares: a^2 -b^2 = (a-b)(a+b) \frac{2}{x^2 -1} - \frac{1}{x-1} = \frac{2}{(x-1)(x+1)} - \frac{1}{x-1} = \frac{1}{x-1}( \frac{2}{(x+1)} -1) = \frac{1}{x-1}( \frac{2 - (x+1)}{(x+1)} ) = \frac{1}{x-1} \frac{2 -x -1)}{(x+1)}= \frac{1}{x-1} \frac{1 -x }{(x+1)} = \frac{1}{x-1} (-1)\frac{x-1}{x+1} = -\frac{1}{x+1}. So the answer to this question is (A) -\frac{1}{x+1}.

[SaqibKhan]

Thanks for sharing solution ibraheem