Imat past paper 2020


How to solve this question?

Hi!

In order to find the turning points first we need to calculate/find the derivative of y and equalizing it to zero which will give us the X coordinate of the T.P.
4Xtp + 5 =0
Xtp = -5/4.

substituting this value in the given Quadratic equation where (x=xtp).
y= 2(-5/4)^2 + 5(-5/4) -2
on solving
y=-41/8.
Thus the coordinates are (-5/4, -41/8) answer is B.
Hope it helps:)

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