Hi!

I broke down the problem like this:

We have 1/3 chance of picking R Y or B

at its simplest form we can pick one candy out of RRR YYY BBB

in the unluckiest scenario that we donâ€™t pick three of the same colour we must have chosen RR YY BB

Now in the jar we have R Y and B left in the same ratio

So whichever colour we pick next we can be sure to form a triplet of the same colour

The answer is 6 + 1 = 7 candies

Hope this helps!

I am lost on this one to be honestâ€¦lol

R(20) Y(20) B(20)

The ratio is easy obviously, but couldnâ€™t I theoretically pick 10 yellows in a rowâ€¦this question makes no sense to me - because theoretically there are 20 candles of each color so you may actually pick 10+ straight of the same color which means you would have to keep pickingâ€¦It is realistic, no - but possible.

I see what you mean, this question is very confusing, i think my logic might be flawed

But in your example if you would have picked 10 yellow candies in a row then you picked more than three of the same colour, which satisfies the question

You are definitely not flawed, I see what it is asking now - sorry sometimes these logic questions take me a minute. It asks for the minimum to have all three. Kind of an odd question.

Hah yes logic questions take forever to solve! Definitely a challenging question!