Logic (TSA 2020)

How should I solve these kinds of problems?
Is it best to just consider every single possibilities? If so, are there any tips to reduce time?

Hey! Can you write the steps you take when approaching this kind of question? It will help me see which steps are maybe redundant and what you can do better. :blush:


Considering option C and E can be easily (30 USD * 10 tickets) or (35 USD * 10 tickets), I only considered option A, B, and D by drawing graphs and subtracting remaining money / remaining ticket numbers.

A. 250D: (2 tickets * 20) + (7 tickets * 30) (There is a mistake in my screenshot)
B. 275 D: (3 tickets * 20) + (6 tickets * 30) + (1 ticket * 35)
D. 325 D: (5 tickets * 35) + (5 tickets * 30)

I somehow got all options possible, so I wanted to check if I made a mistake or something.
Thank you :slight_smile:

+) The correct option is B btw!

first only focus on saturday because all the tickets were bought for saturday.
second this 10 tickets were all bought at once so you cant jump from the price of (first 200 ticket) to (next 500 ticket) . eliminate answer C&E becase 10x30=300$ and 10x35=350$ than the other prices are either (between first 200 and next 300 )or( between next 300 and next 500) so maybe she purchased 5 from last200 tickets and 5 from 300 tickets ( 20x5 +30x5=250$) eliminate A. maybe she purchased 5 from 300 tickets and 5 from 500 tickets(30x5+ 35x5=325$) . the reason i tried 5 was just to try halve from each . you just need to consider possibilities.

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Guess I missed the part where it said one purchase. Thanks!

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