Magnetic field question

An electron with charge -1.6 10^-19 C is subjected to a magnetic field of 2 T which is perpendicular to its speed of 12 107 m/s. What is the intensity of the force exerted on the electron?

Hi!

I made a mistake but i’m not sure where:
I used F = Bqvsin(theta)
F = 2 * (-1,6 * 10⁻¹⁹) * 12 107 * 1
F = - 3,8 * 10^-15

The correct answer is - 3,8 * 10^-12
Is this because i should have changed the units of the magnetic field from Teslas to something else?

Thanks!