Hi!!
Does anybody know how to solve Q54 from the IMAT 2020 past paper? Could anyone explain the way they solve it to me?
Thank you so much in advance!
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Hi!
In order to find the turning points first we need to calculate/find the derivative of y and equalizing it to zero which will give us the X coordinate of the T.P.
4Xtp + 5 =0
Xtp = -5/4.
substituting this value in the given Quadratic equation where (x=xtp).
y= 2(-5/4)^2 + 5(-5/4) -2
on solving
y=-41/8.
Thus the coordinates are (-5/4, -41/8) answer is B.
A summary PDF is made on this topic under maths section and there are also several practice problems you can check it out to make it further clear.
Hope it helps 
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Thank you so much! You made it very clear!
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