an object of 2kg increases in speed from 2 m/s to 4 m/s in 3 s. what was the total work performed on the object during this time interval?
answer: 12 J
can someone explain? thanks
hi
work = change Ek
so work = 1/2mvi² - 1/2mvf²
= 1/2 * 2 * 4² - 1/2 * 2 * 2²
= 16 - 4 = 12J
1/2mvf^2 - 1/2mvi^2?
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