Hi

For A) 1.57* 10^-3N

B) It will float. Vs = 0.88V

C) 6.17 * 10^2 kg/m3

Weight of wax = mg or rho Vg

if u use w = mg then,

m= w/g

m = 0.1572/9.8

m= 0.016kg

rho = m/V

rho = 0.016/26 * 10^-6

rho = 6.17 * 10^2 kg/m3

if u use w = rho V g then,

rho = w/ Vg

rho = 0.1572/26 * 10^-6 * 9.8

rho = 6.17 * 10^2

w gasoline = rho gasoline V g

rho gasoline = w gasoline/Vg

= 6.87 * 10^-3/ 1 * 10^-6* 9.8

= 7.01 * 10^2 kg/m3

weight of wax = weight of liquid displaced

rho V g = rho gasoline Vs(submerged volume) g

Cancel g on both sides,

rho V = rho gas Vs

rho/ rho gas = Vs/ V

Vs/V = 6.17 * 10^2/7.01 * 10^2

Vs/V = 0.88

Vs = 0.88 V

Vs = 0.88 (26 * 10^-6)

Vs = 2.288 * 10^-5 m3

weight of liquid displaced

w = rho gasoline Vs g

w = 7.01 * 10^2 * 2.288 * 10^-5 * 9.8

w = 1.57 * 10^-3N

since rho gas > rho wax, the wax will float.